ÿØÿàJFIFÿþ ÿÛC       ÿÛC ÿÀÿÄÿÄ"#QrÿÄÿÄ&1!A"2qQaáÿÚ ?Øy,æ/3JæݹÈ߲؋5êXw²±ÉyˆR”¾I0ó2—PI¾IÌÚiMö¯–þrìN&"KgX:Šíµ•nTJnLK„…@!‰-ý ùúmë;ºgµŒ&ó±hw’¯Õ@”Ü— 9ñ-ë.²1<yà‚¹ïQÐU„ہ?.’¦èûbß±©Ö«Âw*VŒ) `$‰bØԟ’ëXÖ-ËTÜíGÚ3ð«g Ÿ§¯—Jx„–’U/ÂÅv_s(Hÿ@TñJÑãõçn­‚!ÈgfbÓc­:él[ðQe 9ÀPLbÃãCµm[5¿ç'ªjglå‡Ûí_§Úõl-;"PkÞÞÁQâ¼_Ñ^¢SŸx?"¸¦ùY騐ÒOÈ q’`~~ÚtËU¹CڒêV  I1Áß_ÿÙ"""Bisection algorithms.""" def insort_right(a, x, lo=0, hi=None, *, key=None): """Insert item x in list a, and keep it sorted assuming a is sorted. If x is already in a, insert it to the right of the rightmost x. Optional args lo (default 0) and hi (default len(a)) bound the slice of a to be searched. """ if key is None: lo = bisect_right(a, x, lo, hi) else: lo = bisect_right(a, key(x), lo, hi, key=key) a.insert(lo, x) def bisect_right(a, x, lo=0, hi=None, *, key=None): """Return the index where to insert item x in list a, assuming a is sorted. The return value i is such that all e in a[:i] have e <= x, and all e in a[i:] have e > x. So if x already appears in the list, a.insert(i, x) will insert just after the rightmost x already there. Optional args lo (default 0) and hi (default len(a)) bound the slice of a to be searched. """ if lo < 0: raise ValueError('lo must be non-negative') if hi is None: hi = len(a) # Note, the comparison uses "<" to match the # __lt__() logic in list.sort() and in heapq. if key is None: while lo < hi: mid = (lo + hi) // 2 if x < a[mid]: hi = mid else: lo = mid + 1 else: while lo < hi: mid = (lo + hi) // 2 if x < key(a[mid]): hi = mid else: lo = mid + 1 return lo def insort_left(a, x, lo=0, hi=None, *, key=None): """Insert item x in list a, and keep it sorted assuming a is sorted. If x is already in a, insert it to the left of the leftmost x. Optional args lo (default 0) and hi (default len(a)) bound the slice of a to be searched. """ if key is None: lo = bisect_left(a, x, lo, hi) else: lo = bisect_left(a, key(x), lo, hi, key=key) a.insert(lo, x) def bisect_left(a, x, lo=0, hi=None, *, key=None): """Return the index where to insert item x in list a, assuming a is sorted. The return value i is such that all e in a[:i] have e < x, and all e in a[i:] have e >= x. So if x already appears in the list, a.insert(i, x) will insert just before the leftmost x already there. Optional args lo (default 0) and hi (default len(a)) bound the slice of a to be searched. """ if lo < 0: raise ValueError('lo must be non-negative') if hi is None: hi = len(a) # Note, the comparison uses "<" to match the # __lt__() logic in list.sort() and in heapq. if key is None: while lo < hi: mid = (lo + hi) // 2 if a[mid] < x: lo = mid + 1 else: hi = mid else: while lo < hi: mid = (lo + hi) // 2 if key(a[mid]) < x: lo = mid + 1 else: hi = mid return lo # Overwrite above definitions with a fast C implementation try: from _bisect import * except ImportError: pass # Create aliases bisect = bisect_right insort = insort_right